What's the answer of this puzzle?

x(One shoe) = (30/3)/2 = 5
a(Guy) = 5
b(Two ribbons in wrists) = 4
c(Two ribbons in hands) 4
d(wearing shoes) = 10
y(guy with accessories) = a + b + c + d = 23
z = single ribbon = 2
Answer(applying BODMAS) = x + (y x z) = 51

23

3x = 30 x=10
2y + 10 = 20 y=5
2z + 5 = 13 z=4

Multiplcation before addition

Man is holding ties(2) and half a shoe and only half a tie multiplier.

(10/2)+(5+2+2)×(4/2) =
5 + 9 × 2 =
5 + 18 = 23

23+20 = 43

Shoes on the last dude

3,722

15

15 ( 5 + 5 x 2 )

60

6x=30 x=5
2y+10=20 2y=10 y=5
4z+5=13 4z=8 z=2
5+(5+4+10)*2=a 5+(19*2)=a 5+38= a a=43

17 correction. 20. I mistook the multiplier and forgot to subtract a shoe

30

48. 5+(5+10+4)x2

48 😎

172

19

20

60

15

15

26

1 shoe + guy with 2 ribbons and 2 shoes + 1 ribbon

5+ 5 + 4 + 10 + 2 = 26

30 if normal operator precedence rules apply

One and a half?

Dang the answer is 43.

It took me a while to look into the picture to figure it out lol

60

48, i guess.

DamnifIknow...