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x(One shoe) = (30/3)/2 = 5
a(Guy) = 5
b(Two ribbons in wrists) = 4
c(Two ribbons in hands) 4
d(wearing shoes) = 10
y(guy with accessories) = a + b + c + d = 23
z = single ribbon = 2
Answer(applying BODMAS) = x + (y x z) = 51
a(Guy) = 5
b(Two ribbons in wrists) = 4
c(Two ribbons in hands) 4
d(wearing shoes) = 10
y(guy with accessories) = a + b + c + d = 23
z = single ribbon = 2
Answer(applying BODMAS) = x + (y x z) = 51