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If x is divided by 45, the remainder is 23. What is that number?

If that x is divided by 9, what is the remainder?
Classified · M
x = 45n + 23, with n an integer

If we then do x/9 we get (45n + 23)/9 = 5n + 23/9
So the remainder part is only decided by the 23/9, which is 3 with a remainder of 5.
Classified · M
@Riemann
[quote]If that x is divided by 9, what is the remainder?[/quote]
De question is about x divided by 9. So x/9.
Riemann · 31-35, M
@Classified Ok, suppose this question has only this first part:
If x is divided by 45, the remainder is 23. What is that number?
Then?
Classified · M
@Riemann Then x = 45*n + 23 with n an integer (maybe n also greater or equal than 0)
Because there are an infinite amount of numbers x which satisfy.
[quote]If x is divided by 45, the remainder is 23.[/quote]

The 45*n is divisible by 45, hence the remainder of 45*n + 23 divided by 45 is 23.
ABCDEF7 · M
x = [b]68[/b]

68/45 = 1 Mod 23
68/9 = 7 Mod 5
Riemann · 31-35, M
@ABCDEF7 Can you explain?
ABCDEF7 · M
@Riemann The answer can be a complete series, 68 is the first element of series.
There can be a complete series/graph following the equation 45y + 23. The first number in series would be 68 when you replace y with 1.
The series would be like 68, 113, 158 .. when you relace y with any positive integer

Let consider x as 113,
113/45 = 2 Mod 23
113/9 = 12 Mod 5
eMortal · M
X=45*n + 23, n is any natural number.
For the second question the remainder is 5.
Because 45 or 45n divided by 9 gives no remainder but 23/9 =2 and the remainder is 5. No matter what integer n the answer for the 2nd one is always 5 !!!
Riemann · 31-35, M
@eMortal In the book the remainder is 5.
eMortal · M
You’re right.@Riemann
WaryWitchWandering · 36-40, F
X=1,035

115?

I’m terrible with algebra/math

But I think I’m right?
Riemann · 31-35, M
@WaryWitchWandering I am not good at maths either. I just enjoy; a math and it's solution.
WaryWitchWandering · 36-40, F
@Riemann I izzzz confused
Riemann · 31-35, M
@WaryWitchWandering Let's look at the solution given here by other users. :) <3

 
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