If x is divided by 45, the remainder is 23. What is that number?

If that x is divided by 9, what is the remainder?

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x = 45n + 23, with n an integer

If we then do x/9 we get (45n + 23)/9 = 5n + 23/9
So the remainder part is only decided by the 23/9, which is 3 with a remainder of 5.

Riemann · 31-35, M

@Classified How was the 9 brought?

Classified · M

@Riemann Brought? I'm sorry I do not know what that means in this context, but if you mean this step: (45n + 23)/9 = 5n + 23/9
Then steps in between are (45n + 23)/9 = 45n/9 + 23/9 = (45/9)*n + 23/9 = 5n + 23/9

Riemann · 31-35, M

@Classified I mean how was 9 taken to be placed under x?

Classified · M

@Riemann
[quote]If that x is divided by 9, what is the remainder?[/quote]
De question is about x divided by 9. So x/9.

Riemann · 31-35, M

@Classified Ok, suppose this question has only this first part:
If x is divided by 45, the remainder is 23. What is that number?
Then?

Classified · M

@Riemann Then x = 45*n + 23 with n an integer (maybe n also greater or equal than 0)
Because there are an infinite amount of numbers x which satisfy.
[quote]If x is divided by 45, the remainder is 23.[/quote]

The 45*n is divisible by 45, hence the remainder of 45*n + 23 divided by 45 is 23.