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Quick math test...

Poll - Total Votes: 12
divide by 2 (2 4 6 8 10 etc...)
divide by 3 (3 6 9 12 15 etc...)
divide by 5 (5 10 15 20 25 etc...)
divide by 7 (7 14 21 28 35 etc...)
they are all the same amount
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You can only vote on one answer.
Are there more natural numbers that you can divide be 2 without any remainders or by 3 or by 5 or by 7 ?

explain your answer.
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Iwantyourhotwife · 22-25
It depends on your constraints. Any finite set will have a higher density of numbers divisible by 2 as opposed to 3 and 5, etc. But considering an infinite set, there would be no difference since it could go with no end. Even rate wouldn't matter til it became finite