Space Travel
Did you know staying in Orbit requires very little energy. Once up to 5 miles a second. The rate of fall (due to gravity) will balance the vector of flying off in a straight line. To return to earth you just need to decelerate.
This page is a permanent link to the reply below and its nested replies. See all post replies »
JoyfulSilence · 51-55, M
JoyfulSilence · 51-55, M
@Lisa82
Oh, I was referring to orbital inclination.
I looked it up. A website said that to change from one orbit to another (at the same radius), one needs to wait until one intersects the new orbit. Suppose the old velocity vector there is A, and new one you want is B (where A and B have the same size, just different orientations). Then the delta-v (call it C) should be
C = B - A.
To check this, note that
A + C = A + ( B - A ) = B
So, the larger the angle between A and B, the larger the C.
I also read it is easier if the radius is larger, since then the magnitude of A and B is smaller. In some cases, it requires less energy to instead do the following: ascend, change to a new inclination, then descend.
😵💫
Oh, I was referring to orbital inclination.
I looked it up. A website said that to change from one orbit to another (at the same radius), one needs to wait until one intersects the new orbit. Suppose the old velocity vector there is A, and new one you want is B (where A and B have the same size, just different orientations). Then the delta-v (call it C) should be
C = B - A.
To check this, note that
A + C = A + ( B - A ) = B
So, the larger the angle between A and B, the larger the C.
I also read it is easier if the radius is larger, since then the magnitude of A and B is smaller. In some cases, it requires less energy to instead do the following: ascend, change to a new inclination, then descend.
😵💫
