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OK, if you're going to use the quadratic formula then...
2y^2 -10y -7 = 0
so
a = 2
b = -10
c = -7
replace the a,b and c values in the quadratic formule and you'll get the value of Y
Makes sense?
2y^2 -10y -7 = 0
so
a = 2
b = -10
c = -7
replace the a,b and c values in the quadratic formule and you'll get the value of Y
Makes sense?
Candypie2010 · 26-30, F
@drymer ya thanks
ImRileyTheDog · 22-25, F
@drymer Why are you making is equal to 0 when the problem is 2y^2[b]=[/b]10y -7
drymer · 56-60, M
@ImRileyTheDog To get the a, b and c values for the quadratic formula...
ImRileyTheDog · 22-25, F
@drymer But it already as an equal sign in the equation, you just get rid of it and throw it at the end then equal 0? I don't recall doing that for some reason.