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You're incredibly attractive... I mean, if you were any heavier, you'd collapse under your own mass into a black hole.

F=GMm/(r^2). xD Attractive. Gravity. You know... physics joke. Although if you had a fat/wg thing, this put down line would be more of a pickup line. Ew. xD

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LoquaciouslyLucid

But wait...wouldn't you be calling them dense? Assuming they were a rotund sphere, such such that V= (4/3)(r^3)(pi) , and their density was X unit of mass per cubic meter or what not? Basically, the volume would be Mass/Density = Volume, and ( (volume)(3/4)(1/pi))^(1/3) would be the new radius? Meaning that the radius would effectively be ((M kg x ( 1cubic meter/ X kg)(3/4)(1/pi))^1/3 , so if M doubled the radius would increase by roughly 2^(1/3) , or effectively, since R is squared in the gravity equation, 2^(2/3)? ... Though, come to think of it, than the gravity does grow larger, and oh god, you're right xD

TetrisGuy · 26-30, M

Yep! Read my other comments. xD

LoquaciouslyLucid

But wait! The larger X is, the slower the radius grows compared to the mass, no? Meaning that dense people would collapse sooner, anyhow, so long as they kept growing

TetrisGuy · 26-30, M

Whoops I was about to respond to this, and tabbed away, and then forgot to reply to it. Well it all depends on the density. After a particular point it'll collapse. It's a pretty sharp drop off.

TetrisGuy · 26-30, M

And if you kept feeding them mass they keep growing. The evaporation rate is an uncomfortably simple formula o.o

LoquaciouslyLucid

Well, I meant that both would collapse eventually, but that the difference in the ratio between mass and radius would grow at different rates depending on the density. Or something along those lines... I was feeling very sleepy at the time