Interesting coincidence on the Middle East hijacking.

Using the physics behind gravity. Distance traveled by a dropped object in vacuum with gravity of 32 feet per second per second.=1/2Gravity muliply Time Squared. So we know the airplane dropped 14000 feet. D =14000 so 14000 X 2 equals 28000. 28000 divided by 32 = about 875. Square root of 875 = 29. Therefore the time it would take to drop 14,000 feet in zero gravity freefall would be 29 seconds. Hmmm How long did they say it took to go those 14000 feet? 29 seconds! It is almost like someone used a calculator is it not?

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Quimliqer · 70-79, MVIP

The editor said “make it plausible!!

hippyjoe1955 · 70-79, M

@Quimliqer The funny part is that the numbers actually don't work! Vertical speed starts at zero and at the end of 29 seconds returns to zero so how fast did it accellerate both up and down? Well it rurns out that it is about 68 feet per second per second or about 2.125 Gs. Its max speed down only is about 660 MPh. If it were traveling forward at 500 MPh it would have reached about 933 MPH which is Mach 1.3 which brings in the shock waves incountered in the transonic supersonic atmosphere. If it happened as described the airplane would be a debris field somewhere in the desert.

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