If your favorite number isn't 1, then it's 10.

@DeWayfarer I think that would still work.

@Luke73 nope! π never repeats. Same with the natural logrhythm [i]e[/i].
You would have to know the end of either.

Though the later there is some hypothesis that there is a correlation to bases. Not π however.

@DeWayfarer As a base you can also chose irrational numbers, so you can have a base with e or π too. For writing numbers, you have to chose a base/radix and factors for each digit, that are smaller than your base. For example, you can use π as the base and chose the factor has to be of the set of {0, 1, 2, 3}. With that you can have a representation of any real number.

@Luke73 then you're inaccurate. So again wouldn't work.

At what point would you round up? 🤷🏻‍♂️

Represent this your way...
9π

The higher the x value in xπ the higher the inaccuracy.

@DeWayfarer That would be an infinite series, it would start with 222.021120021...
9π is around 28.275 if you calculate 2π^2+2π+2+2/π^2+1/π^3 you get around 28.257

@Luke73 but... [quote]The higher the x value in xπ the higher the inaccuracy.
[/quote]

@DeWayfarer What do you mean by that? With infinite many digits you get the exact number

@Luke73 it's infinite! There's no set "RATIONAL" value!

@DeWayfarer So is for π in base 10. But you can still use π as a base. And the representation for π in base π is 10.

@Luke73 not with accuracy!

8 in base is a accurate! 10 base eight!

@DeWayfarer It is it exact because it's π. You write any real number in a base as the sum from i to negative infinity over a factor times your based raised to the power of i. And by that 10 in base π is 1*π^1 + 0*π^0 + 0*π^-1 + 0 + ... And the only part of the sum that isn't 0 is 1*π^1 which is exactly π. And thus 10 in base π is exactly π.

@Luke73 no because there's no representation for infinite digits to round up!

Your using base 3 represention.

@DeWayfarer No, I'm using base π with the digits 0, 1, 2. Type it in a calculater and you'll see. With base 3 it would be 222.021 you would get 24.259... with base π you get a different value, so I use base π.

What do you mean with that there is no representation for ininite digits to round up?

@Luke73 to accurately represent base π you must follow it with an infinite series. You have done it yourself. Yet the very fact that it's an infinite series is inaccurate. It's irrational. Not rational.

@DeWayfarer You can represent π with an infinite series in base 10 too, you can represent any real number with an infinite series in base 10. It's how real numbers are defined, whether they're rational, irrational, transcendental, it doesn't matter, they're all real numbers.

@Luke73 I'm just going to have to say that I totally disagree. There's no need to represent base 10 with an infinite series. You absolutely must with base π

@DeWayfarer In base π there are also numbers which don't need an infinite amount of digits, like π or 2π or π^2 those all can be represented by a finite amount of digits.

@Luke73 once again I totally disagree.

[center][big][b][i][c=1F5E00]𝓗𝓪𝓿𝓮 𝓪 𝓰𝓸𝓸𝓭 𝓭𝓪𝔂! 😊[/c][/i][/b][/big][/center]

@DeWayfarer You can disagree or not, you're in the wrong here.

Sure have a good day.

@Luke73 base three isn't base π! 🤷🏻‍♂️

@DeWayfarer Yes, I know, but I can use π as a base too regardless.

@Luke73 not without representation.

@DeWayfarer What do you mean without representation? 10 is a real number, π is a real number, I can use the golden ration too.

@Luke73 gave a fair representation yourself. As far as it went. Because the series is infinite it's still irrational.

@DeWayfarer What does it change if the series is infinite or not? It's a real number in the end. It's just a value, there is no need for it to be rational.