Where are the math people? I have a question
If you have 3 six sided dice, how many rolls would you have to make (on average) before they all showed the same digit?
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Northwest · M
If you pick any single number, let's say 3.
Individually, you would need to roll one dice, at minimum, 6 times to possibly get a 3. That's the minimum probability.
So, that's 1/6, and each roll is a separate event. So, 6 events for each dice, and each dice is 1/6, you end up with: 1/6 * 1/6 * 1/6 * 6 = 1/36, or 36 different attempts are required to get the minimum probability.
The upper bound is limitless, because each roll of the dice, represents an individual event.
Individually, you would need to roll one dice, at minimum, 6 times to possibly get a 3. That's the minimum probability.
So, that's 1/6, and each roll is a separate event. So, 6 events for each dice, and each dice is 1/6, you end up with: 1/6 * 1/6 * 1/6 * 6 = 1/36, or 36 different attempts are required to get the minimum probability.
The upper bound is limitless, because each roll of the dice, represents an individual event.