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polynomial identity 1
(x+y)^2= x^2+2xy+y^2
now if x=60 & y=3
Then (60+3)^2 =60^2+2*60*3+3^2
=3600+360+9= 3969
63^2=63×63=3969 so
(60+3)^2=63^2
(x+y)^2= x^2+2xy+y^2
now if x=60 & y=3
Then (60+3)^2 =60^2+2*60*3+3^2
=3600+360+9= 3969
63^2=63×63=3969 so
(60+3)^2=63^2
Lostpoet · M
I ain't doing your homework bro
PrivateHell · M
Dude. I already have to teach my son math (my absolute least favorite subject) every day for homeschooling. Do your own homework.
Domking · 61-69, M
Similarly polynomial identity 3
(x+y)*(x-y)=x^2-y^2
If x=10 & y=1
(10+1)×(10-1)=10^2-1^2
11×9=100-1
99=99
(x+y)*(x-y)=x^2-y^2
If x=10 & y=1
(10+1)×(10-1)=10^2-1^2
11×9=100-1
99=99
Fertilization · 36-40, F
This is easy. You just have to concentrate on your class work.