Help me with this math question please
The height of a triangle is 6 m more than twice the length of the base. The area of the triangle is 18 m2. Find the height of the triangle. ??
26-30, F
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Roflcash4 · 22-25, M
h=2b+6
A=18
A=1/2bh
18=1/2b(2b+6)
multiply both sides by 2 to get 36=b(2b+6)
distribute the b to get 36=2b^2+6b
subtract 36 from both sides to get 0=2b^2+6b-36
Factor to get 0=2b^2+12b-6b-36 and simplify to get (2b-6)(b+6)
Set both factors to zero to get b=-6 and b=3
The length of the base can't be negative so the base has to be 3m and the height is 2(3)+6=12m.
A=18
A=1/2bh
18=1/2b(2b+6)
multiply both sides by 2 to get 36=b(2b+6)
distribute the b to get 36=2b^2+6b
subtract 36 from both sides to get 0=2b^2+6b-36
Factor to get 0=2b^2+12b-6b-36 and simplify to get (2b-6)(b+6)
Set both factors to zero to get b=-6 and b=3
The length of the base can't be negative so the base has to be 3m and the height is 2(3)+6=12m.