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midnightsun · 26-30, M
It's simple. Since it's an isolated and frictionless system, use law of conservation of momentum.
Momentum of bullet before penetration = momentum of bag + momentum of bullet after penetration
Momentum formula is mass* velocity
Momentum of bullet before penetration = momentum of bag + momentum of bullet after penetration
Momentum formula is mass* velocity
midnightsun · 26-30, M
The answer..here you go
Hanging2 · 51-55, M
@midnightsun you are right sir
midnightsun · 26-30, M
@Hanging2 thanks
Deadcutie · 18-21, F
I’d just take the 8pt penalty
Sadpicasso · 22-25, F
@Deadcutie felt that
CheshireCatalyst · 36-40, M
Is it as simple as subtraction? Because it's a frictionless surface there would be no lost energy so the kinetic energy of the bullet would be transferred to the flour?
So if that's right: the bag is moving at 185m/s?
So if that's right: the bag is moving at 185m/s?
CheshireCatalyst · 36-40, M
@CheshireCatalyst mine is wrong. I forgot how to maths
TheRascallyOne · 31-35, M
Witch craft
Lanyx · 41-45, M
Total momentum before = Total momentum after
Momentum of bullet + momentum of flour = Momentum of bullet + momentum of flour
mass * velocity + mass * velocity = mass * velocity + mass * velocity
plug in and solve.
Momentum of bullet + momentum of flour = Momentum of bullet + momentum of flour
mass * velocity + mass * velocity = mass * velocity + mass * velocity
plug in and solve.
SW-User
The bullet lost 185 m/s from its speed, and since the bag of flour is about 100 times the weight of the bullet, that would be about 1.85 m/s
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deadgerbil · 22-25
Ice isn't frictionless tho? 🤔
TheCoolestCat · 31-35, M
62mph
PoizonApple · 41-45, F
ts;dr