Only logged in members can reply and interact with the post.
Join SimilarWorlds for FREE 禄

Soooo whats the answer ? 馃馃馃

馃馃馃馃馃馃檮
MasterofNone26-30, M
The value of the shoes is 10
The value of the guy is 5
The value of those ribbon like things are 4
So, 5 + 5 x 2 = 15
It's trickier than that though lol.
MasterofNone26-30, M
@SW-User but that guy has worn two shoes and two of those ribbon like things in his hands so I wonder if it's
5 + 19 x 2 = 43
SW-User
@MasterofNone potentially.... Really sneaky and I think makes it a bit pointless as now it becomes a debate not a maths problem. Lol
MasterofNone26-30, M
@SW-User Yeah lol the question can get really pointless. What if the economists say that one shoe has no value and it is only when the two meet that it can be counted 10 as a whole. Ughh I pass. Lol
SW-User
15

Unless we're getting into the fact that the man is wearing trainers in the last one. But that's just getting ridiculous
60

Edit: 5+15*2 = 40 so not 60
SW-User
@DoctorChristian how you get 15 is that five for the guy and five each for his shoes?
@SW-User Yes
SW-User
@DoctorChristian so wearing is implied addition not multiplication? 馃
Chap040641-45, F
Very instresting i had come up with 60
JoyfulSilence46-50, M
5+((5+5+5+2+2)脳2)

=43
[c=#359E00]26.5?[/c]
SW-User
minarth00861-69, M
MrBrownstone46-50, M
Mysti51-55, F
0
Newfound41-45, M

 
Post Comment